X^2+12.5x+36=0

Solution for X^2+12.5x+36=0 equation:

X^2+12.5X+36=0

a = 1; b = 12.5; c = +36;
Δ = b2-4ac
Δ = 12.52-4·1·36
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.5)-\sqrt{12.25}}{2*1}=\frac{-12.5-\sqrt{12.25}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.5)+\sqrt{12.25}}{2*1}=\frac{-12.5+\sqrt{12.25}}{2}
$